Question
Six years ago, a father was 5 times as old as his son.
After 6 years, the father will be 3 times as old as the son. What is the son’s present age?Solution
Let present ages be F and S 6 years ago: F - 6 = 5(S - 6) F - 6 = 5S - 30 F = 5S - 24 After 6 years: F + 6 = 3(S + 6) F + 6 = 3S + 18 F = 3S + 12 Equating: 5S - 24 = 3S + 12 2S = 36 S = 18
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