Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
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36895 - 4256 - 2233 = ?
20 * 8 + 40% of 100 + 60% of 150 = ?
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(96 ÷ 8 + 72 ÷ 9) * 3
60 = (? x 10 + 250)/5
17% of 250 + ? = 108
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? × 18 + 3072 ÷ 24 = 20% of 1900
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If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
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