Question
If in the given number, 4756783234, all the digits are arranged in ascending order, and then one is added to each digit. After that 1st and 6th, 2nd and 7th, 3rd and 8th and so on digits are interchanged with each other in the same order, then what is the sum of all the odd place digits (starting from the first digit from the left end) after the rearrangement?Â
Solution
4Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 4 2Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8 3Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 9 6Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 5 Sum of odd place digits after the rearrangement is: 6 + 8 + 9 + 4 + 5 = 32.
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