Question
If in the number '632456372', '1' is added to all the
odd digits and '2' is subtracted from the all the even digits then, all the digits are arranged in ascending order from left to right. What is the sum of first four digits from the left end of the number thus formed?ÂSolution
6Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 2 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 0 0Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8 So, the sum of the first four digits from the left end is = (0 + 0 + 2 + 4) = 6.
What will come in the place of question mark (?) in the given expression?Â
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...162 ÷ [51 – {29 – (9 – 6̅ ̅+̅ ̅7̅ )}]=?
 {(481 + 426) 2 - 4 × 481 × 426} = ?
180 % of 45 + √144 × 8 = ?2  + 80 % of 70
What will come in the place of question mark (?) in the given expression?
642 - 362 = ? X √1225
500% of (121.8 + 16.4 – 28.2) = ? × 2
- Find the simplified value of the expression:
81 ÷ 9 of 3 × 4 + [12 of 5 – {18 of 2 × (10/5) ÷ 36}] – 15 √196 + (0.25 × 144) + 19 = ? + 72
√(?) ² = √7396 - √6889
36% of 250 + 26 ÷ 2 × ? = 207
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