Question
If in the number '632456372', '1' is added to all the
odd digits and '2' is subtracted from the all the even digits then, all the digits are arranged in ascending order from left to right. What is the sum of first four digits from the left end of the number thus formed?ÂSolution
6Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 2 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 0 0Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8 So, the sum of the first four digits from the left end is = (0 + 0 + 2 + 4) = 6.
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