Question
Simplify: 8sin 27° sec 63° + 3cot 64° cot
26°Solution
8sin 27° sec 63° + 3cot 64° cot 26° = 8sin 27° sec (90° - 27°) + 3cot (90° - 26°) cot 26° Using, sec (90° - A) = cosec A and cot (90° - A) = tan A = 8sin 27° cosec 27° + 3tan 26° cot 26° Since, cosec A is reciprocal of sin A and cot A is reciprocal of tan A. = 8 + 3 = 11
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(a) Se2–
(b) SeO–
(c) SeO23–
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