Question
cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚
x cot 86˚= ?Solution
We know that If cotA x cotB = 1 then A & B are complementary angles it means A + B = 90˚ Here 4˚ + 86˚ = 90˚ , 47˚ + 43˚ = 90˚ & 42.3˚ + 47.7˚ = 90˚ So cot 4˚ x cot 86˚ = 1, cot 47˚ x cot 43˚ = 1 & cot 42.3˚ x cot 47.7˚ = 1 Hence cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚ x cot 86˚= 1
The minimum value of 25 sin2 θ + 16 cos2 θ is
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