Question
cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚ x cot 86˚= ?
Solution
We know that If cotA x cotB = 1 then A & B are complementary angles it means A + B = 90˚ Here 4˚ + 86˚ = 90˚ , 47˚ + 43˚ = 90˚ & 42.3˚ + 47.7˚ = 90˚ So cot 4˚ x cot 86˚ = 1, cot 47˚ x cot 43˚ = 1 & cot 42.3˚ x cot 47.7˚ = 1 Hence cot 4˚ x cot 47˚ x cot 42.3˚ x cot 43˚ x cot 47.7˚ x cot 86˚= 1
More Trigonometry Questions
- which of the following is equal to [(tan θ +secθ -1)/ (tanθ-secθ +1)]
- If √3cosec 2x = 2, then the value of x:
- If 4cos²A + 5sin²A = 4.5, then find the value of (sec²A - 1)
- If X = 15°, find the value of: sin²(3X) + cos²(4X) - tan²(2X)
- If tan θ = 8/3 , then the value of (3Sinθ+2 Cosθ )/(3 Sinθ-2Cosθ) is
- Find the value of the given trigonometric expression: (sin 25°cos 65° + cos²25°) × sin 30° + (cos 60°tan 45°) × sec 60°
- Evaluate the following: sin 60° × cos 30° − sin 30° × cos 60°
- Simplify (cos13°+sin 13°) /(cos13°-sin13°)
- If sin θ and cos θ are the root of standard Quadratic Equation , then which of the following is true ? 1. a2 + b2 - 2ac = 0 2. b2 - a2 + 2ac = 0 3. a 2 + ...
- If sin x + cos x = √2 sin x, then the value of sin x - cos x is: