New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    If tan3θ = 1, then find the value of: (sin² 2θ/sec 3θ +

    15°)
    A √3/4 Correct Answer Incorrect Answer
    B 1/3 Correct Answer Incorrect Answer
    C 2 + √2 Correct Answer Incorrect Answer
    D 1/8 Correct Answer Incorrect Answer

    Solution

    Given tan 3θ = 1

    So, 3θ = 45 o

    So, θ = 45/3 = 15 o

    So, (sin² 2θ/sec 3θ + 15°) = (sin² 30°/sec 45° + 15°)

    = (sin² 30°/sec 60°) = (½)²/2 = 1/8

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