Question
If tan3θ = 1, then find the value of: (sin² 2θ/sec 3θ +
15°)Solution
Given tan 3θ = 1
So, 3θ = 45 o
So, θ = 45/3 = 15 o
So, (sin² 2θ/sec 3θ + 15°) = (sin² 30°/sec 45° + 15°)
= (sin² 30°/sec 60°) = (½)²/2 = 1/8
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