Question
If sec A + tan A = (9/4) and sec A - tan A = (4/9),
find the value of cos A.Solution
sec A + tan A = (9/4) ---------- (I) sec A - tan A = (4/9) --------- (II) on adding (I) and (II) , we get; 2sec A = (97/36) Or, sec A = (97/72) So, cos A = (1/sec A) = (72/97)
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