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Always remember that cot & tan are compliment to each other So tan ɵ = cot( 90-ɵ) So it is given that cot5A = tan(3A-14˚) Hence 5A + 3A - 14˚= 90˚ So 8A - 14˚ = 90˚ or 8A = 90˚+14˚=104˚ or A = `104^@/8` = 13˚
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