Question
Solution
Above expression can be written as = with the help of (a + b)3  = a3  + b3  + 3ab (a + b) a2  – b2  = (a + b) (a – b) (a + b)2  = a2  + b2  +2ab = (cos2 θ + sin2 θ)3  / cosec θ sec θ [sin2 θ + cos2 θ + 2sin θ cos θ – 1] = 1 / 1/sin θ cos θ [1 + 2sin θ cos θ – 1] = 1/2
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