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Above expression can be written as = with the help of (a + b)3 = a3 + b3 + 3ab (a + b) a2 – b2 = (a + b) (a – b) (a + b)2 = a2 + b2 +2ab = (cos2 θ + sin2 θ)3 / cosec θ sec θ [sin2 θ + cos2 θ + 2sin θ cos θ – 1] = 1 / 1/sin θ cos θ [1 + 2sin θ cos θ – 1] = 1/2
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