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    Question

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    A 3 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 1 Correct Answer Incorrect Answer
    D 1/2 Correct Answer Incorrect Answer

    Solution

    Above expression can be written as = with the help of (a + b)3 ┬а= a3 ┬а+ b3 ┬а+ 3ab (a + b) a2 ┬атАУ b2 ┬а= (a + b) (a тАУ b) (a + b)2 ┬а= a2 ┬а+ b2 ┬а+2ab = (cos2┬а ╬╕ + sin2┬а ╬╕)3 ┬а/ cosec ╬╕ sec ╬╕ [sin2┬а ╬╕┬а + cos2 ╬╕ + 2sin ╬╕ cos ╬╕ тАУ 1] = 1 / 1/sin ╬╕ cos ╬╕ [1 + 2sin ╬╕ cos ╬╕ тАУ 1] = 1/2

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