Question
If sinAo = (√3/2), then find the value of
(sin245o + cos230o) × A ÷ 5 given that 0 < A < 90.Solution
A = sin-1 (√3/2) = 60 sin245o + cos230o X A ÷ 5 = {(1/√2)2 + (√3/2)2} x 60 ÷ 5 = {(1/2) + (3/4)} × 12 = (5/4) × 12 = 15
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