Question
Train 'A' is 160 metres long and can cross a pole in 8 seconds. It is crossed by train 'B', which is 200 metres long and running at a speed of 108 km/hr, in 36 seconds (same direction). Find the time taken by train 'A' to cross a platform of length 120 metres.
Solution
Speed of train A = 
m/s Speed of train B = 108 × (5/18) = 30 m/s Relative speed (same direction) = 30 – 20 = 10 m/s Time to cross train B = 36 s: l + 200 = 10 x 36 = 360 so, l = 360 – 200 = 160 m Time to cross platform of length 120 m = (160 + 120)/20 = 14 sec
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