Question
A train running with the speed of 38 m/s crosses a man
walking with the speed of 5 m/s in the same direction in 10 seconds, find the length of train.Solution
According to the question, Let the length of the train be x meter. Let S1 and S2 be the speed of train and speed of man. => (S1 – S2) = (Length of train)/Time => (38 - 5) = x/10 => x = 330 m Length of train = Distance travelled = 330 meter.
If  x = a(b - c), y = b(c – a) and z = c(a - b) , find the value of (x/a)3 + (y/b)3 + (z/c)3?
If a + b + c = 12 and ab + bc + ca = 30, then find the value of a² + b² + c².
If [x + (1/x)] = 3, find [x2 + (1/x2)].

If 'x' is the lowest positive integer divisible by 8, 12 and 20, then find the second smallest positive integer which is divisible by all the three giv...
If x + y = 10 and xy = 21, find value of x³ + y³.
Solve the inequality for real x:
3 − 2x ≤ (x + 1)/2 < 5
The speed of a car is 25% more than that of a bike. Both of them start from a same point. After travelling for 4 hours, the speed of the bike is increas...
If (a2 + 1/a2) = 27, then find the value of (a3 - 1/a3).