Let the speed one train be x m/s and the speed of the second train be y m/s. Length of the first train = Speed × Time = 24x Length of second train = Speed × Time = 14y So, {(24x + 14y)/(x+y)} = 20 ⇒ 24x + 14y = 20x + 20y ⇒ 4x = 6y Therefore, x:y = 3:2
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