Question
Train X, traveling at a speed of 54 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 90 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 5:3, and train X crosses a pole in 40 seconds, find the value of (t + 11).Solution
Length of train X = 40 × 54 × (5/18) = 600 m Length of train Y = (600/5) × 3 = 360 m => t = (600 + 360)/[(54 + 90) ×(5/18)] = 24 sec Required value = (t + 11) = 24 + 11 = 35
Q=0.138 h² √h is a formula to calculate:
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