Question
Train 'A' is 480 meters long and crosses a pole in 24
seconds. It also crosses Train 'B' in the opposite direction in 12 seconds. If Train 'B' is twice as long as Train 'A', then find the distance travelled by Train 'B' in 45 minutes.Solution
Speed of Train 'A' = 480 ÷ 24 = 20 m/s Length of Train 'B' = 2 × 480 = 960 meters Combined length of Train 'A' and 'B' = 480 + 960 = 1440 meters Relative speed of Train 'B' w.r.t Train 'A' = 1440 ÷ 12 = 120 m/s So, speed of Train 'B' = 120 − 20 = 100 m/s = 100 × (18/5) = 360 km/h Distance covered by Train 'B' in 45 minutes = 360 × (45/60) = 270 km
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