Question
The length of a rectangle is 10 cm more than its width.
If the perimeter of the rectangle is 40 cm, find the area of the rectangle.Solution
Let the width be x. Length = x + 10. Perimeter of the rectangle = 2 × (Length + Width) = 40. 2 × (x + (x + 10)) = 40. Simplifying: 2 × (2x + 10) = 40, 4x + 20 = 40, 4x = 20, x = 5. Length = 5 + 10 = 15. Area = Length × Width = 15 × 5 = 75 cm².
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to:
What will come in the place of question mark (?) in the given expression?
{(2/15) + (12/25)} of 375 + 190 = ?% of 375
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 17
2850 ÷ 2.5 - ? × 42 = 300
[4(2/3) + 5(1/6)] × 45% of 240 = ?
√2025 + √1024 - √1296 = 20% of ?
If 1210 ÷ 22 + 1332 ÷ 37 - y + 54 × 3 = 980 ÷ 20 × 144 ÷ 48, then the value of y is:
What will come in the place of question mark (?) in the given expression?
(308 – 154) ÷ 11 = ? ÷ 15
28 × 3.5 +25 × 3.2 = ? - 62
What will come in place of the question mark (?) in the following expression?
25% of 2000 – 50% of 500 = 100% of ?
