Question
Train P travelling at 42 km/hr crosses another train Q,
having three fourth of its length and travelling in opposite direction at 30 km/hr in 21 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.Solution
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (42 + 30) x 5/18 = {x + (3x/4)}/21 ⇒ 72 x 5/18 = (7x/4)/21 ⇒ x = 240 m Therefore, let the length of the platform be y metre ⇒ 42 x 5/18 = (240 + y)/36 ⇒ 420 = 240 + y ⇒ y = 420 – 240 = 180 m
20.132 ÷ 62.5% of 11.16 = ? + 5109.21
7.992 + (4.01 × 3.98) + ? = 224.03
88% of 1620 + 29² = ? + 1482 ÷ 18
35.1% of 1599 = ?–(449.96 ÷ 6.12) × 2
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
 (3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
((341.789)1/3 × (0.0049)1/2)× 429.798/6.88 =?
40.02% of 1220.05 = ?2 + 29.09 × 7.99
15.35 x (58.25 + 63.98) = ? + 1029.78
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