Question
850 metres long train crosses a man who is moving in the same direction with a certain speed, in 50 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.
Solution
Speed of train = 850/20 = 42.5 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (42.5 β s) m/sec According to the question, (42.5 β s) = 850/50 Or, s = 42.5 β 17 = 25.5 Therefore, speed of the man = 25.5 m/sec
More Trains Questions
- Two trains βT7β and βU7β of lengths 540 metres and 360 metres respectively are travelling towards each other. Ratio of speed of βT7β to βU7β is 3:1. If the...
- A train crosses a 500-metre-long platform in 30 seconds, and the same train crosses a tunnel that is 20% longer than the train itself in 42 seconds. Find t...
- A train 150 m long passes a pole in 10 seconds. Find its speed in km/h.
- There are two trains A and B. A start from point X at 5 AM towards point Y. Another train B starts at 7 AM from point Y. If they meet at 9 AM and speed of ...
- A train covers a distance of 180 km in 4 hours 30 minutes. What is its average speed?
- A man is running at a speed of 10 m/sec in the same direction of the train. Train can cross the man in 6 seconds. If speed of the train is 108 km/hr, then ...
- Two cyclists start from villages R and S which are 234 km apart. One starts from R at 6:45 a.m. at 36 km/h. Another from S at 7:45 a.m. at 54 km/h towards ...
- A train has to cover a distance of 112 km in 14 hours. If it covers half journey in 3/5th time, then the speed of covering the remaining distance in the ti...
- A train crosses a pole and a platform of length 504 metres in 9 seconds and 21 seconds, respectively. Find the length of train.
- Two trains βT5β and βU5β of lengths 800 metres and 400 metres respectively are travelling towards each other. Ratio of speed of βT5β to βU5β is 5:3. If the...