Question
850 metres long train crosses a man who is moving in the
same direction with a certain speed, in 50 seconds. If the same train can cross a tree in 20 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 850/20 = 42.5 m/sec Let the speed of the man be βsβ m/sec Relative speed of the train = (42.5 β s) m/sec According to the question, (42.5 β s) = 850/50 Or, s = 42.5 β 17 = 25.5 Therefore, speed of the man = 25.5 m/sec
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