Question
Train 'M' takes 2 hours less than Train 'N' to travel a
distance of 150 km. The speed of Train 'M' is 20 km/h more than that of Train 'N'. What is the time taken by Train 'N' to cover a distance of 360 km?Solution
Let the speed of train 'N' be 'v' km/h. Speed of train 'M' = (v + 20) km/h ATQ, 150/v - 150/(v + 2) = 2 Or, 150(v +2) - 150v = 2v (v + 10) Or, v2Â + 50v - 30v - 1,500 = 0 Or, v(v + 50) - 30(v + 50) = 0 Or, (v + 50) (v - 30) = 0 So, 'v' = 30 or 'v' = - 50 Speed cannot be negative. So, 'v' = 30 Therefore, time taken by train 'N' to cover 360 km = (360/30) = 12 hoursÂ
(400.01% of 149.89) ÷ 49.97 = ?2 ÷ (95.98 ÷ 31.99)Â
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
What approximate value will replace the question mark (?) in the following?
29.99...
(4913)1/3  × 10.11 × 13.97 ÷ 20.32 = ? + 39.022
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
120.02% of 599.90 + (34.78/20.89) × (47.98) = ?2 – 10.022
6.992 + (2.01 × 2.98) + ? = 175.03
509.85 ÷ 15.05 + 210.16 – 18.06 × 5.95 = ?
124.88% of 60.101 + 18.09% of 849.87 – 22.12% of 1049.93= ? – 19.93