Question
A train with a length of (p + 60) meters takes 30
seconds to cross a platform that is (q + 60) meters long while traveling at a speed of 20 meters per second. If the same train takes 12 seconds to pass a tree, determine the value of 'q'.Solution
ATQ, [(p + 60) + (q + 60)]/ 20 = 30 p + q + 120 = 600 p + q = 600 β 120 p + q = 480 -----(i) Also, (p + 60)/20 = 12 (p + 60) = 12 Γ 20 p = 240 β 60 p = 180 m So, q = 480 β 180 = 300 m
(1.01) 0 + (2.02) 1 + (2.93) 2 + (4.04) 3 + (5.05) 4 = ?
49.97% ofΒ 2016 β 37.99% of 1050 = ? β 47.98% of 5950
124.88% of 60.101 + 18.09% of 849.87 β 22.12% of 1049.93= ? β 19.93
(√4623.9 + √484.2) – √2303.97 ÷ √1296.4 × √35.98 ÷ √15.99 = ?
√ ({(5.5 × 2.3) × √ (728.91))} = 3(1/7) ÷ ?/28
...111.89 Γ 4.12 β 504.04 Γ· 2.12 = 170.12 + ?
2 (1/4)% of 7999.78 + {49.77% of 899.71} + β144.14 - 20% of 1499.83 = ?
44.78% of 715.62 + 1785% of 42.98 = ?
(1560.23 Γ· 25.98) + (768.32 Γ· 23.9) + 1814.11 = ?
70.14% of 799.95 - 240.12 = ? + 40.17% of 299.95