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ATQ,
Let the speed of train 'X' be 'x' km/h
Distance covered by train 'X' in first 2 hours = 2 × x = 2x km
Time both trains travelled together = 7 hours (from 9:00 a.m. to 4:00 p.m.)
ATQ;
7 × (65 + x) = 760 - 2x
Or, 455 + 7x = 760 - 2x
Or, 305 = 9x
So, x = 33.88
So, speed of train 'X' = 33.88 km/h
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