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    Question

    A 360 m long train crosses a platform twice its length

    in 3 min. Find the speed of the train. Section 1
    A 4 m/s Correct Answer Incorrect Answer
    B 5 m/s Correct Answer Incorrect Answer
    C 6 m/s Correct Answer Incorrect Answer
    D 7 m/s Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Speed of train = (Length of train + Length of Platform)/Required time Length of train = 360 m Crossing time of platform = 3 Γ— 60 = 180 sec Length of platform = 360 Γ— 2 = 720 m Let the speed of train be x. Speed of train = (360 + 720)/180 β‡’ Β x = 6 m/s

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