Question
Train ‘A’ can cross a pole in 10 seconds and a 200
metre long platform in 14 seconds. If the ratio of length of train ‘A’ and train ‘B’ is 2:5, respectively, then find the time taken by train ‘B’ to cross a pole with a speed of 25 m/s.Solution
Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 10s Also, 14s = 10s + 200 Or, 4s = 200 Or, s = 50 Therefore, length of train ‘A’ = 10s = 500 metres Length of train ‘B’ = 500 × (5/2) = 1250 metres Required time taken = 1250 ÷ 25 = 50 seconds
__________ primarily provides insight into how effective network control and practices are, i.e. its compliance to internal and external network policie...
Which of the following configurations provides a higher voltage gain in an op-amp?
What is the main characteristic of a greedy algorithm?
Kirchhoff's Current Law (KCL) is based on the principle of:
Which data processing technique is commonly used for handling large-scale data in distributed computing environments?
What is Inter-Process Communication (IPC) in the context of computer systems?
What is depth in deep learning?
Which is the first process launched by the LINUX?
The truth table for an OR gate has an output of 1 when:
Consider a 4-way set associative cache consisting of 128 lines with a line size of 64 words. The CPU generates a 20-bit address of a word in main memor...
