Question
Train βAβ can cross a pole in 10 seconds and a 200
metre long platform in 14 seconds. If the ratio of length of train βAβ and train βBβ is 2:5, respectively, then find the time taken by train βBβ to cross a pole with a speed of 25 m/s.Solution
Let the length and speed of the train βAβ be βlβ metre and βsβ m/s, respectively. According to question, l = 10s Also, 14s = 10s + 200 Or, 4s = 200 Or, s = 50 Therefore, length of train βAβ = 10s = 500 metres Length of train βBβ = 500 Γ (5/2) = 1250 metres Required time taken = 1250 Γ· 25 = 50 seconds
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