Question
Train ‘A’ can cross a pole in 10 seconds and a 200
metre long platform in 14 seconds. If the ratio of length of train ‘A’ and train ‘B’ is 2:5, respectively, then find the time taken by train ‘B’ to cross a pole with a speed of 25 m/s.Solution
Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 10s Also, 14s = 10s + 200 Or, 4s = 200 Or, s = 50 Therefore, length of train ‘A’ = 10s = 500 metres Length of train ‘B’ = 500 × (5/2) = 1250 metres Required time taken = 1250 ÷ 25 = 50 seconds
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
79.99% of (84.89 × 5.99) - (3.89)2 × 21.87 = ?
(29.892 × √290) + 32.98 × 6.91 = ?
44.84% of 799.94 + (625.21 ÷ 24.91) – √(224.77) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09
[54.96 × √99.96 – {(25.02/6.84)% of 280.24}]/(3.032 × 19.87) = ?
