Question
10 rotten bananas are accidentally mixed with 140 good
ones. It is not possible to just look at a banana and tell whether or not it is rotten. One banana is taken out at random from this lot. Determine the probability that the banana is taken out is a good one.Solution
Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 140 + 10 = 150 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 140/150 = 14/15
12, 16, ?, 36, 52, 72
What will be the approximate value of the following questions.
√675 + √785 = ? × 8.995
‘A’ and ‘B’ can build a wall in 8 days and 12 days, respectively. If ‘A’ started building the wall alone but after 4 days he was replaced by...
? = 650.24 + 1124.97 – 14.992
What approximate value will replace the question mark (?) in the following?
34.99...
25.31% of 5199.90 + (19.9 × 17.11) + 46.021 =? + 168.98
19.92 × (52.065/260.07) × (45.09% of 359.87) =?
(1295.98)(1/4) + {40.02% of 150.09} × {√48.98 – √15.98} = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
