Question
Two dice are thrown simultaneously. Find the probability
that sum of the numbers appeared on both the dice is at least 7.Solution
Total number of outcomes = 6 x 6 = 36
Favourable outcomes = {(1,6), (2,5), (2,6), (3,4), (3,5), (3,6), (4,3), (4,4), (4,5), (4,6), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
=> Number of favourable outcomes = 21
Required probability = 21/36 = 7/12
What will come in place of (?) question mark in the following expression.
 (√1296 ÷ √36) × ? = 120
Find the value of ?
{[(864 ÷ 18) ÷ 8] ÷ 3} + 11² – 2³ = ?
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
Simplify the following expressions and choose the correct option.
(5/9 of 486) + (3/4 of 224) - (25% of 364)
12.5% of (100 + ?) = 40
30% of 8/5 × 5/7 × 2870 =?
(1/5)(40% of 800 – 120) = ? × 5
Simplify the expression:
(5x + 15) / (x² + 3x)
116 x (2/3)% of 420 + 666 x (2/3)% of 186 = 457 x (1/7)% of 126 + 555 x (5/9)% of 198 + ?
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