Question
Two dice are thrown simultaneously. Find the probability
that sum of the numbers appeared on both the dice is at least 7.Solution
Total number of outcomes = 6 x 6 = 36
Favourable outcomes = {(1,6), (2,5), (2,6), (3,4), (3,5), (3,6), (4,3), (4,4), (4,5), (4,6), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
=> Number of favourable outcomes = 21
Required probability = 21/36 = 7/12
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