Question
A box contains 8 yellow marbles, ‘x’ blue marbles
and 12 white marbles. A box contains 5 yellow marbles, 2 blue marbles and 3 white marbles. The probability of drawing a blue marble at random from the box is 1/6. If (x/2) blue marbles from the box is transferred to the bag, then find the probability of drawing a blue marble and a white marble from the boxSolution
According to the question, x/(8 + x + 12) = 1/6 => 5x = 20 => x = 4 Therefore, number of blue marbles transferred to box = x/2 = 2 Total number of blue marbles in the bag after the transfer = 2 + 2 = 4 Total number of marbles in the box after the transfer = 5 + 2 + 3 + 2 = 12 Required probability = (4C1 × 3C1 )/12C2 = 2/11
More Probability Questions
(42% of 1500 + 170) ÷ 4 = ?2 - 52Â
18 × √225 + 378 ÷ √441 = ? × 9Â
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
Find the value of x.
 √441 ÷ 21+ √400 = 1 × x
What will come in the place of question mark (?) in the given expression?
642 - 362 = ? X √1225
(21% of 360) ÷ 0.8 =?
√324 + √576 = ?/ √9
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