Question
200 metre long train ‘A’ can cross a platform of
length 180 metres in 10 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(200 + 180)/10} = (380/10) = 38 m/s Speed of train ‘B’ = 38 + 6 = 44 m/s = 44 × (18/5) = 158.4 km/hr Required distance travelled by train ‘B’ = 158.4 × 5 = 792 km
More Trains Questions
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
28.95% of 924.78 + 1955% of 38.99 = ?
? + 151.99 – 100.01 = 23.01 × 4.98
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
37.06% of 783.45 + 2125% of 51.89 = ?
2 (1/4)% of 7999.58 + {49.06% of 898.87} + √143.14 – 19.99% of 1499.63 - (52 - 41) = ?
1254.04 – 440.18 + 399.98 ÷ 10.06 = ?
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