Question
200 metre long train βAβ can cross a platform of
length 180 metres in 10 seconds. If the speed of train βBβ is 6 m/s more than that of train βAβ, then find the distance travelled by train βBβ in 5 hours.Solution
Speed of train βAβ = {(200 + 180)/10} = (380/10) = 38 m/s Speed of train βBβ = 38 + 6 = 44 m/s = 44 Γ (18/5) = 158.4 km/hr Required distance travelled by train βBβ = 158.4 Γ 5 = 792 km
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