Question
200 metre long train ‘A’ can cross a platform of
length 180 metres in 10 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(200 + 180)/10} = (380/10) = 38 m/s Speed of train ‘B’ = 38 + 6 = 44 m/s = 44 × (18/5) = 158.4 km/hr Required distance travelled by train ‘B’ = 158.4 × 5 = 792 km
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