Question
250 metre long train ‘A’ can cross a platform of
length 180 metres in 20 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(250 + 180)/20} = (430/20) = 21.5 m/s Speed of train ‘B’ = 21.5 + 6 = 27.5 m/s = 27.5 × (18/5) = 99 km/hr Required distance travelled by train ‘B’ = 99 × 5 = 495 km
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...What will come in place of the question mark (?) in the following series?
81, 83, 87, 95, 111, ?
48, 24.5, ?, 39.75, 81.5, 206.25, 621.75
What value should come in the place of (?) in the following number series?
14, 18, ?, 43, 68, 104
14, 20, 29, 44, 65, ?
16, 16, 32, 96, ?, 1920
What will come in place of (?) Question mark in the given number series.
500, 489, 467, 434, 390, 335, ?
72, 79, 100, 135, 184, ?
79Â Â Â Â Â 86Â Â Â Â Â Â 76 Â Â Â Â Â Â 89Â Â Â Â Â Â 73 Â Â Â Â Â Â ?
...290, 571, 900, ?, 1485, 1890
