Question
250 metre long train ‘A’ can cross a platform of
length 180 metres in 20 seconds. If the speed of train ‘B’ is 6 m/s more than that of train ‘A’, then find the distance travelled by train ‘B’ in 5 hours.Solution
Speed of train ‘A’ = {(250 + 180)/20} = (430/20) = 21.5 m/s Speed of train ‘B’ = 21.5 + 6 = 27.5 m/s = 27.5 × (18/5) = 99 km/hr Required distance travelled by train ‘B’ = 99 × 5 = 495 km
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