Question
Sachin can complete a job in 15 days. Ankit alone can
complete the same job in 10 days. Sachin works for 9 days and then the remaining job is completed by Ankit. How many days will it take Ankit to complete the remaining job alone?Solution
Sachin’s 1 day work = 1/15 days
∴ Sachin’s 9 days work = 9/15 = 3/5days,
∴ Remaining work = 1 - 3/5 = 2/5 part of the work.
Ankit completes 1 work in 10 days.
∴ Ankit will complete 2/5 part of the work in `10xx2/5` = 4 days.
Alternate Method:
Sachin Ankit
Time taken 15 10
Total work = LCM 30 units
2 : 3
Sachin's 9 days work = `2xx9` = 18 units
So remainning work = 30 - 18 = 12 units which is completed by Ankit alone in = 12/3= 4 days
More Important Reports and Indices Questions
Simplify: 60 ÷ 5 × 3 + 8 × (7 − 4)
- What will be come in place of (?) in the given expressions.
√324 + (18 × 5) – 72 ÷ 8 = ? 1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
(22 + √3364)/(? + 4) = 10
360 ÷ 9 + 15 % of 200 + ? * 10 = 45 * √25
- Evaluate: 156 ÷ 12 × 4 + 180 – 40% of 350
447.8 × 441.2 ÷ 445 = 44 × 44?
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
What will come in the place of question mark (?) in the given expression?
?2 = 3945 ÷ 5 + 774 ÷ 6 – 77Â
If 1560 ÷ 30 + 2025 ÷ 45 - z + 33 × 7 = 1848 ÷ 24 × 234 ÷ 39, then the value of z is:
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