Question
A piece of work consists of 360 identical units. A can
do (x + 4) units per day and B can do (x β 2) units per day. They work together for 9 days and the remaining work is completed by A alone in 5 more days. In how many days can B alone complete the entire work?Solution
ATQ, Total work = 360 units Aβs speed = (x + 4) units/day Bβs speed = (x β 2) units/day Work done in first 9 days by A and B together = (x + 4 + x β 2) Γ 9 = (2x + 2) Γ 9 = 18x + 18 Remaining work done by A in 5 days = (x + 4) Γ 5 = 5x + 20 Total work = (18x + 18) + (5x + 20) = 360 23x + 38 = 360 23x = 322 x = 14 So Aβs speed = 14 + 4 = 18 units/day Bβs speed = 14 β 2 = 12 units/day Time taken by B alone = 360 / 12 = 30 days
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