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      Question

      β€˜A’, β€˜B’ and β€˜C’ can complete a piece of

      work in 60 days, 120 days and 80 days respectively. β€˜A’ and β€˜B’ started the work together but β€˜A’ left the work after 15 days. Now β€˜C’ joined the work and then after 9 days β€˜B’ is replaced by β€˜A’. Find the time taken to complete the rest of the work by β€˜A’ and β€˜C’ together.
      A 15 days Correct Answer Incorrect Answer
      B 18 days Correct Answer Incorrect Answer
      C 21 days Correct Answer Incorrect Answer
      D 24 days Correct Answer Incorrect Answer

      Solution

      Let total amount of work = 240 units (LCM of 60, 120 and 80) Amount of work done by β€˜A’ in one day = 240/60 = 4 units Amount of work done by β€˜B’ in one day = 240/120 = 2 units Amount of work done by β€˜C’ in one day = 240/80 = 3 units Amount of work done by β€˜A’ and β€˜B’ together in 15 days = 15 Γ— 6 = 90 units Amount of work done by β€˜B’ and β€˜C’ together in 9 days = 9 Γ— 5 = 45 units Remaining work = 240 – 90 – 45 = 105 units Time taken by β€˜A’ and β€˜C’ together to complete the remaining work = 105/7 = 15 days

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