Question
‘P’ is 20% more efficient than ‘Q’. ‘P’ can
do a piece of work in 15 days. They begin the work together, but ‘Q’ leaves after 6 days. The rest of the work is completed by ‘P’ in ‘x’ days. What is the value of ‘x’?Solution
ATQ, Time taken by ‘Q’ to complete the work = 1.2 × 15 = 18 days Let the total work be 90 units Efficiency of ‘P’ = 90/15 = 6 units/day Efficiency of ‘Q’ = 90/18 = 5 units/day Work done by ‘P’ and ‘Q’ in 6 days = (6 + 5) × 6 = 66 units Therefore, x = (90 – 66)/6 = 24/6 = 4 days
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