Question
βPβ is 20% more efficient than βQβ. βPβ can
do a piece of work in 15 days. They begin the work together, but βQβ leaves after 6 days. The rest of the work is completed by βPβ in βxβ days. What is the value of βxβ?Solution
ATQ, Time taken by βQβ to complete the work = 1.2 Γ 15 = 18 days Let the total work be 90 units Efficiency of βPβ = 90/15 = 6 units/day Efficiency of βQβ = 90/18 = 5 units/day Work done by βPβ and βQβ in 6 days = (6 + 5) Γ 6 = 66 units Therefore, x = (90 β 66)/6 = 24/6 = 4 days
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