Question
A train crosses a bridgeĀ in 15 secs while it crosses a
man standing on a platform in 8 secs. If the speed of train 108 km/hrs, then what will be the time taken by the train to cross a tunnel whose length is 210 meters more than the length of the bridgeĀ .Solution
ATQ, we can say that Speed of trainĀ is = (108 x 5)/18 = 30 m/s then, the Length of bridgeĀ is = 30 x 7 = 210 mĀ {The "30 Ć 7" step comes from: Extra time over bridge = 15 ā 8 = 7 sec = Bridge length = 30Ć7 = 210 m} then, the Length of tunnel = 210 + 210 = 420 m Length of trainĀ 108 Ć 5/18 = (x + 210)/15 30 Ć 15 = x + 210 x = 240 meter therefore, the Required time = (240 + 420)/30 = 22 seconds
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