Question
Train 'C' running with a speed of 90 km/hr crosses a
pole in 8 seconds. In how much time will train 'C' cross train 'D' whose length is 80 meters more and speed is 40% more than 'C', which is running in the opposite direction of 'C'?Solution
ATQ, Speed of train 'C' = 90 × (5/18) = 25 m/sec Therefore, length of train 'C' = 25 × 8 = 200 meters Length of train 'D' = 200 + 80 = 280 meters Speed of train 'D' = 25 + (25 × 0.4) = 35 m/sec Required time taken = (200 + 280) / (25 + 35) = 480 / 60 = 8 seconds
28         57           172           689          ?              20677
...14 26 50 98 194 ?
...5                             6                             14              �...
89Â Â Â Â Â 78Â Â Â Â Â 74Â Â Â Â Â 67Â Â Â Â Â 63Â Â Â Â ?
100Â Â Â Â 221Â Â Â Â 77Â Â Â Â 245Â Â Â Â 50Â Â Â 275
Identify the logic of the below given series and given answer.
Series I :: 1840, 1719, (P), 1694, 1890, 1665, 1921
Series II :: 175, 4...
(45)2 ÷ ∛729 + (35)2 ÷ 1.4 =?
17                          26                          37                   �...
25 30 300 315 6300 ?
...2, 12, 90, 240, ?, 1260
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