Question
Train βXβ is travelling with a speed of 90 km/hr
and crosses a vertical pole in 6 seconds. Train βYβ is 30 metres longer than βXβ and travelling with a speed 1/5th less than that of train 'X'. In how much time train Y can cross a 180 metres long platform?Solution
Speed of train βXβ = 90 Γ (5/18) = 25 m/sec Length of train βXβ = 25 Γ 6 = 150 metres Therefore, speed of train βYβ = (4/5) Γ 25 = 20 m/sec Length of train βYβ = 150 + 30 = 180 metres Required time taken = (180 + 180)/20 = 18 seconds
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