Question
Compute P(AǀB), if P(B) = 1.0 and P(A∩B) =
0.64Solution
Given: P (B) = 1.0 and P(A∩B) = 0.64 We know that by definition of conditional probability, => P(AǀB) = [P(A∩B)]/P(B) Now by substituting the values we get, => P(AǀB) = 0.64/1.0 = 16/25
- What will come in the place of question mark (?) in the given expression?
5555 ÷ 11 ÷ 5 = 100 +? 216% of 350 + 273 = ?2 × 21
(70% of 480) ÷ 6 + ? = 45% of 3500 + 802 + 272
What will come in place of (?) in the given expression.
√625 + 12 × 5 = ?If (3 × 144 – 252 ÷ 14) ÷ 18 = √1024 – x, then find the value of ‘x’.
1231 + 1312 + 2113 – 3211 = ?
(96% of 1100) + 92 × 4 = ? + 46 × 16
What will come in the place of question mark (?) in the given expression?
(252 + 198) ÷ ? + 126 ÷ 3 = 144 ÷ 2