Question
The distance between (4, –1) and (–8,
y) is 13. Find possible values of y.
Solution
ATQ,
Distance formula: (4 + 8)² + (–1 – y)² = 169 12² + (–1 – y)² = 169 144 + (y + 1)² = 169 (y + 1)² = 25 y + 1 = ±5 y = 4 or –6 Answer: y = 4 or y = –6
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