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ATQ, Speed of Bike = 140/1.4 = 100 km/h Distance travelled by Truck = 100 × 2 = 200 km - Quantity I Distance from point R to point S = d km d/(10 + 2) + d/(10 – 2) = 41.25 d/12 + d/8 = 41.25 5d/24 = 41.25 d = 198 km Quantity II < Quantity I
Angle of friction and angle of repose are
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