Question
Amit and Anaya can complete a task together in 20 days. If
Anaya is 150% more efficient than Amit, how many days will Anaya alone take to finish the task?Solution
ATQ,
Let the efficiency of Amit alone = 4 units/day
Then, efficiency of Anaya alone = 4 + 4 × 1.5 = 10 units/day
So, total work = (4 + 10) × 20 = 280 units
And so, time taken by Anaya alone to complete the work = 280 ÷ 10 = 28 days
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