Question
'Amit' alone can do some work in 15 days. 'Bunty' is 40%
more efficient than 'Amit'. 'Amit' worked alone for 4 days and left. How much time (in days) does 'Bunty' need to finish the remaining work?Solution
Let the efficiency of 'Amit' be 'a' units/day So, efficiency of 'Bunty' = 1.4 x a = '1.4a' units/day Total work = 15 x a = '15a' units Work done by 'Amit' in four days = 4 x a = '4a' units Time taken by 'Bunty' to finish the remaining work = {(15a – 4a)/1.4a} = 7(6/7) days
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