Question
A and B working together completed a job in 40/9 days. If A had worked twice as efficiently as she did and B had worked 1/3 of his actual efficiency, then the work would have been completed in 60 /17 days. Find the time A would take to complete the work alone.
20A=25B A/B=25/20 A/B=5/4 A: B=5:4 ATQ- Total work= (40/9) ×9 =40 Total work completed by A = 40/5=8 daysMore Time and work Questions
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