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    Question

    A bus was travelling from Jaipur to Udaipur was delayed

    by 15 minutes and made up for the delay on a section of 85 km travelling with a speed 12 km per hour higher than its normal speed. Find the approximate original speed of the bus?
    A 66.25 km/hr Correct Answer Incorrect Answer
    B 58.32 km/hr Correct Answer Incorrect Answer
    C 65.15 km/hr Correct Answer Incorrect Answer
    D 58.15 km/hr. Correct Answer Incorrect Answer

    Solution

    Let original speed = 'x' km/hr. Time to cover 85 km at normal speed = 85/x . Time to cover 85 km at increased speed (x+12) = 85/(x+12) Time difference = 15 minutes = 1/4 hours Simplify and solve:

    Solve quadratic equation: Using the quadratic formula, x = 58.15  x = 58.15 km/hr.

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