Question
A police man goes after a thief who has 100m start. If
the policeman runs a KM in 8 min and the thief runs a km in 10 min, how far will the thief have gone before he is overtaken?Solution
Speed of policeman = 1km/8min = 1km/(8/60) = 7.5 kmph Speed of thief = 1km/ (10min) = 1km/(10/60) = 6kmph So time = Distance /speed = 100m /(7.5-6)kmph = 0.1km/ 1.5kmph = 1/15 hrs = 4min Distance travelled by theif in 4min = 6kmph x 4min = 6 x 5/18 x 4 x 60 m = 400m & he has also start of 100m, so total distance travelled by thief till he overtook by policeman= 100m+400m = 500m
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
Find the approximate value of Question mark(?). No need to find the exact value.
(34.95 × 7.03) ÷ 5 + 27.98% of 249.88 – √(80.81) = ?
...What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
9.89 x 4.99 + 2.01 x 49.89 = ?% of 299.69
What approximate value will replace the question mark (?) in the following?
29.99...
What will be the approximate value of the following questions.
(74.75% of 600.29 – 44.85% of 399.99) × (√224.95 ÷ 15.01) = ?
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
12.03 x 4.21 +19.95% of 300.05 =Â ?
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 × 199.98
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