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ATQ,
Downstream speed = 12km/hr. Upstream speed = 3/4 ×12 = 9km/hr. Downstream time for 72km = 72/12 = 6 hrs Let upstream distance = 'x' km. Upstream time = x/9. Given: Upstream time is 3hours more than downstream time:. (x/9) - 6 = 3. Solve = x/9 = 9 x = 81
√2703.88 × √784.15 – 26² = ? - (34.85)²
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
25.09 × (√15 + 19.83) = ? of 19.87 ÷ 4.03
Direction: Please solve the following expression and choose the closest option
52.08% of 645.92 + 1840% of 47.96 = ?
19.99% of 79.98 = ?2– 159.99% of 12.5
19.97% of 3/5 ÷ (1 ÷ 74.99) = ?
30.22% of (61.9 × 5.01) + 69.97 =?
1199.98 ÷ 40.48 × 20.12 = ? × 3.16
88% of 900.23 + 74.99 = ?