Question
A car moving at a speed of 54 km/hr covers a certain
distance in ‘x’ hours. If the same distance is covered at a speed of 72 km/hr in (x - 1.5) hours, find the value of ‘x’.Solution
ATQ, 54x = 72(x - 1.5) 72x – 54x = 108 18x = 108 x = 6
More Time and distance Questions
What will be the product of smaller roots of both equations.Â
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
I). p2 + 17p - 234 = 0
II). q2 - 21q + 108 = 0
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0
I. 6x2 - 41x+13=0
II. 2y2 - 19y+42=0
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
- What should be the value of t in the equation x² + tx + 64 = 0 so that it has two equal real roots?
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 13x² - 60x + 47 = 0
Equation 2: 17y² - 80y + 63 = 0
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