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      Question

      A traveler at four-fifths of his normal speed takes 20

      minutes longer than his usual time to reach his destination. What is his usual travel time?
      A 19 min Correct Answer Incorrect Answer
      B 12 min Correct Answer Incorrect Answer
      C 20 min Correct Answer Incorrect Answer
      D 25 min Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the usual speed of the traveler be '5s' km/h and the distance be 'd' km.

      Let the usual time taken be 't' hours.

      ATQ;

      (d/5s) = t

      Or, d = 5ts ........ (I)

      Traveling at four-fifths of his normal speed:

      (d/(4s)) = t + (20/60)

      Using equation (I), we have;

      (5ts/4s) = t + (1/3)

      Or, 5t = 4t + (1/3)

      Or, t = (1/3)

      Thus, the usual time taken by the traveler to reach his destination = (1/3) hours or 20 minutes.

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