Question
A bus initially traveling at a speed of 55 km/hr
increased its speed by 12 km/hr after ‘t’ hours and then traveled for (t + 6) hours more. If the bus covered 744 km in the last (t + 6) hours, find the distance covered in the first ‘t’ hours.Solution
ATQ, (55 + 12) × (t + 6) = 744 Or, 67 × (t + 6) = 744 Or, t + 6 = 11 Or, t = 5 Therefore, required distance traveled = 55 × 5 = 275 km
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