Question
Two cars ‘X’ and ‘Y’, which were 750 km apart,
started traveling towards each other at the same time and met after 6 hours. If the speed of car ‘X’ is 10 km/h more than the speed of car ‘Y’, then find the speed of car ‘X’.Solution
ATQ,
Sum of the distance travelled by both cars = 750 km
Let the speed of car Y = ‘x’ km/h
So, speed of car X = ‘x + 10’ km/h
So, 6x + 6(x + 10) = 750
Or, 6x + 6x + 60 = 750
Or, 12x = 690
Or, x = 57.5
So, the speed of car X = (x + 10) = (57.5 + 10) = 67.5 km/h
4.5 times 5/0.9× 35% of 240 =?
Simplify the expression:
(4x² - 16) / (2x - 4)
116 ÷ 280 of 1/2 + 3/5 × 5/3 = ?
(23 × 8) – (13 × 5) + 67 =? x 6
212 + 14 × 23 – 28 × 15 = ?
7(1/7)% of 3500 + 6(2/3) % of 6000 = ? + 552.5
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
What value should come in the place of (?) in the following questions?
3(1/2) + 5(1/2) = ? + 4(3/8)
What will come in the place of question mark (?) in the given expression?
128 + 16 X 6 - ? = 88 + 4 X 26
{(8× 8 + 3 × 39) - 620 ÷ 20} = ?
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