Question
‘A’ and ‘B’ started moving towards each other at
same time with a speed of 22 km/hr and 14 km/hr, respectively. If the distance covered by ‘A’ is 40 km more than that by ‘B’, when they meet then find the initial distance between them.Solution
ATQ, Time = Distance/ Relative Speed = 40/(22-14) = 40/8 = 5 Hrs.  Distance between them = (14+22) × 5 = 180 kmÂ
41.98% of 2200.031 + 15% of 3999.9 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?). No need to find the exact value.
18.07 × (47.998 ÷ 12.03) + 59.78% of 150.14 – √(255.86) = ...
4.93% of 539.92-48% of 4700=?-8330.33
177.05 = 25.06% of 3631.97 + 16.02% of 3750.08 – ?3Â
? = 460.24 + 1057.97 – 14.992 Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 16.08 + 13.99 × 25.07
24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)